[C] Minary Fights with Time
- 时间限制: 1000 ms 内存限制: 65535 K
- 问题描述
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Minary is busy now. As a result, she's fighting with time.
To serialize every time point she marked, she decide to make every time point to an integer.
You can imagine that 1970-01-01 00:00:00 GTM(Greenwich Mean Time) is the start. Give you an integer that indicates the total seconds from that time, you should output the time it stands for.
- 输入
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This problem contains several cases, input until EOF.
Every case is an integer(-2^31 ~ 2^31-1) that indicates the total seconds from 1970-1-1 00:00:00 GTM.
- 输出
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For every case, you should output its time.
- 样例输入
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0 1111111111 1363592469 2147483647
- 样例输出
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1970-01-01 00:00:00 2005-03-18 01:58:31 2013-03-18 07:41:09 2038-01-19 03:14:07
- 提示
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无
- 来源
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Minary
- 操作
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