• [B] Big Mouth of Abyss - Kog'Maw

  • 时间限制: 1000 ms 内存限制: 65535 K
  • 问题描述
  • The game LOL is an interesting game. Recently we are playing this game. Once I used a champion named Kog'Maw - The Mouth of the Abyss.
    For I have to support teammate, I only have a little time to do the last hit to kill the enemy's minions.
    There're N (2 <= N <= 10000) minions, each minion has a threat value TVi (1 <= TVi <= 9).
    And there's a formula to calculate the total threat value:



    I only can kill K (1 <= K < N) minions.
    When I kill one minion, the minions after it will move to front for one step. It means when I kill Minion[5], then Minion[6] will be Minion[5] and Minion[7] will be Minion[6] and so on.
    How to kill the minions that I can leave the minimum total threat value?
  • 输入
  • This problem contains several cases.
    Each case contains two numbers. The first number T is the total threat value at the very beginning (1 <= T < 10^10001). Then follows an integer K, means the number that minions I can kill.
  • 输出
  • For each case, you should output the minimum total threat value after I kill K minions.
  • 样例输入
  • 123456 4
    3212311 4
    
  • 样例输出
  • 12
    111
    
  • 提示
  • 来源
  • Ne123123
  • 操作

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